![]() ![]() ![]() ![]() I arbitrarily guessed around 8, and I'm glad I was close, but I'd like to know how to calculate this.įirst you need to know the formula for the probability of a repeat repeat number with exactly n spins. What I really want to know is what formula you used to come up with that number. On a slight tangent, since some of you may enjoy this, I e-mailed James Randi ( for those not familiar), and he was willing to accept challenges from people who claim to have betting systems that can beat the house edge, especially if they're charging for access to those systems. I just smile and politely collect their money. Players come to my table all the time and tell me about their new system and how I have to read _ because it's going to put me out of a job. What is the chance of *any* repeater? And how do I calculate it? Let's say we're not calling a number first, but simply some random number coming up twice? To put some numbers out there, On a 38 number wheel across 10k spins, how many repeating numbers can I expect to see?Īs for the ball not having a memory. Now with that in mind, I should probably alter my question a bit. Thanks for the post, a little light went on in my head when I read this that the 38^2 is only if you're calling the number beforehand and that *that* number hits twice. ![]()
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